Search a number
-
+
14534443345 = 52906888669
BaseRepresentation
bin11011000100101001…
…00000000101010001
31101111221010020000111
431202110200011101
5214231304141340
610402123321321
71023114505252
oct154224400521
941457106014
1014534443345
116189350454
122997680241
1314a8263546
149bc476b29
155a1001aea
hex362520151

14534443345 has 4 divisors (see below), whose sum is σ = 17441332020. Its totient is φ = 11627554672.

The previous prime is 14534443303. The next prime is 14534443381. The reversal of 14534443345 is 54334443541.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1767025296 + 12767418049 = 42036^2 + 112993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14534443345 is a prime.

It is a super-2 number, since 2×145344433452 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14534443298 and 14534443307.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1453444330 + ... + 1453444339.

It is an arithmetic number, because the mean of its divisors is an integer number (4360333005).

Almost surely, 214534443345 is an apocalyptic number.

It is an amenable number.

14534443345 is a deficient number, since it is larger than the sum of its proper divisors (2906888675).

14534443345 is an equidigital number, since it uses as much as digits as its factorization.

14534443345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2906888674.

The product of its digits is 691200, while the sum is 40.

Adding to 14534443345 its reverse (54334443541), we get a palindrome (68868886886).

The spelling of 14534443345 in words is "fourteen billion, five hundred thirty-four million, four hundred forty-three thousand, three hundred forty-five".

Divisors: 1 5 2906888669 14534443345