Base | Representation |
---|---|
bin | 10101001001101000010… |
… | …111110010111001100111 |
3 | 12010221121102121212000112 |
4 | 111021220113302321213 |
5 | 142303131200424221 |
6 | 3031412234003235 |
7 | 210002563164401 |
oct | 25115027627147 |
9 | 5127542555015 |
10 | 1453450014311 |
11 | 51044a707139 |
12 | 1b583157651b |
13 | a70a1361489 |
14 | 504c1205b71 |
15 | 27c1a83b15b |
hex | 152685f2e67 |
1453450014311 has 2 divisors, whose sum is σ = 1453450014312. Its totient is φ = 1453450014310.
The previous prime is 1453450014281. The next prime is 1453450014371. The reversal of 1453450014311 is 1134100543541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1453450014311 - 222 = 1453445820007 is a prime.
It is a super-2 number, since 2×14534500143112 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1453450014371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726725007155 + 726725007156.
It is an arithmetic number, because the mean of its divisors is an integer number (726725007156).
Almost surely, 21453450014311 is an apocalyptic number.
1453450014311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1453450014311 is an equidigital number, since it uses as much as digits as its factorization.
1453450014311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 1453450014311 its reverse (1134100543541), we get a palindrome (2587550557852).
The spelling of 1453450014311 in words is "one trillion, four hundred fifty-three billion, four hundred fifty million, fourteen thousand, three hundred eleven".
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