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145351320433 = 1182091609667
BaseRepresentation
bin1000011101011110011…
…1010010001101110001
3111220011210011010100021
42013113213102031301
54340134414223213
6150435023123441
713333640560414
oct2072747221561
9456153133307
10145351320433
1156709038410
1224205a43581
1310925449aa7
14706c221b7b
153baa922d8d
hex21d79d2371

145351320433 has 8 divisors (see below), whose sum is σ = 158584491360. Its totient is φ = 132121385280.

The previous prime is 145351320397. The next prime is 145351320451. The reversal of 145351320433 is 334023153541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145351320433 - 29 = 145351319921 is a prime.

It is a super-2 number, since 2×1453513204332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145351330433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 714535 + ... + 895132.

It is an arithmetic number, because the mean of its divisors is an integer number (19823061420).

Almost surely, 2145351320433 is an apocalyptic number.

It is an amenable number.

145351320433 is a deficient number, since it is larger than the sum of its proper divisors (13233170927).

145351320433 is a wasteful number, since it uses less digits than its factorization.

145351320433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1617887.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 145351320433 its reverse (334023153541), we get a palindrome (479374473974).

The spelling of 145351320433 in words is "one hundred forty-five billion, three hundred fifty-one million, three hundred twenty thousand, four hundred thirty-three".

Divisors: 1 11 8209 90299 1609667 17706337 13213756403 145351320433