14535517441 has 2 divisors, whose sum is σ = 14535517442. Its totient is φ = 14535517440.

The previous prime is 14535517433. The next prime is 14535517457. The reversal of 14535517441 is 14471553541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14194339600 + 341177841 = 119140^2 + 18471^2 .

It is an emirp because it is prime and its reverse (14471553541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14535517441 - 2³ = 14535517433 is a prime.

It is a super-3 number, since 3×14535517441³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14535517394 and 14535517403.

It is not a weakly prime, because it can be changed into another prime (14535517471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7267758720 + 7267758721.

It is an arithmetic number, because the mean of its divisors is an integer number (7267758721).

Almost surely, 2^14535517441 is an apocalyptic number.

It is an amenable number.

14535517441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14535517441 is an equidigital number, since it uses as much as digits as its factorization.

14535517441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 168000, while the sum is 40.

The spelling of 14535517441 in words is "fourteen billion, five hundred thirty-five million, five hundred seventeen thousand, four hundred forty-one".