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145356215203 is a prime number
BaseRepresentation
bin1000011101011111100…
…1111101001110100011
3111220012010100210201001
42013113321331032203
54340142142341303
6150435320052431
713334030305033
oct2072771751643
9456163323631
10145356215203
1156710880981
1224207604117
13109264719c4
14706cb378c3
153bab08d31d
hex21d7e7d3a3

145356215203 has 2 divisors, whose sum is σ = 145356215204. Its totient is φ = 145356215202.

The previous prime is 145356215167. The next prime is 145356215233. The reversal of 145356215203 is 302512653541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145356215203 - 221 = 145354118051 is a prime.

It is a super-2 number, since 2×1453562152032 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145356215233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72678107601 + 72678107602.

It is an arithmetic number, because the mean of its divisors is an integer number (72678107602).

Almost surely, 2145356215203 is an apocalyptic number.

145356215203 is a deficient number, since it is larger than the sum of its proper divisors (1).

145356215203 is an equidigital number, since it uses as much as digits as its factorization.

145356215203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 145356215203 its reverse (302512653541), we get a palindrome (447868868744).

The spelling of 145356215203 in words is "one hundred forty-five billion, three hundred fifty-six million, two hundred fifteen thousand, two hundred three".