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145372512053 is a prime number
BaseRepresentation
bin1000011101100011100…
…0000111111100110101
3111220020021000202210002
42013120320013330311
54340210330341203
6150441101241045
713334315651516
oct2073070077465
9456207022702
10145372512053
1156719aa1a4a
1224210b63185
1310929959702
147070d7aa0d
153bac70bd88
hex21d8e07f35

145372512053 has 2 divisors, whose sum is σ = 145372512054. Its totient is φ = 145372512052.

The previous prime is 145372512041. The next prime is 145372512071. The reversal of 145372512053 is 350215273541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108597929764 + 36774582289 = 329542^2 + 191767^2 .

It is a cyclic number.

It is not a de Polignac number, because 145372512053 - 28 = 145372511797 is a prime.

It is a super-2 number, since 2×1453725120532 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 145372511998 and 145372512016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145372512073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72686256026 + 72686256027.

It is an arithmetic number, because the mean of its divisors is an integer number (72686256027).

Almost surely, 2145372512053 is an apocalyptic number.

It is an amenable number.

145372512053 is a deficient number, since it is larger than the sum of its proper divisors (1).

145372512053 is an equidigital number, since it uses as much as digits as its factorization.

145372512053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126000, while the sum is 38.

Adding to 145372512053 its reverse (350215273541), we get a palindrome (495587785594).

The spelling of 145372512053 in words is "one hundred forty-five billion, three hundred seventy-two million, five hundred twelve thousand, fifty-three".