14540212101 has 4 divisors (see below), whose sum is σ = 19386949472. Its totient is φ = 9693474732.

The previous prime is 14540211971. The next prime is 14540212103. The reversal of 14540212101 is 10121204541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14540212101 - 2⁹ = 14540211589 is a prime.

It is a super-2 number, since 2×14540212101² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14540212103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2423368681 + ... + 2423368686.

It is an arithmetic number, because the mean of its divisors is an integer number (4846737368).

Almost surely, 2^14540212101 is an apocalyptic number.

It is an amenable number.

14540212101 is a deficient number, since it is larger than the sum of its proper divisors (4846737371).

14540212101 is an equidigital number, since it uses as much as digits as its factorization.

14540212101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4846737370.

The product of its (nonzero) digits is 320, while the sum is 21.

Adding to 14540212101 its reverse (10121204541), we get a palindrome (24661416642).

The spelling of 14540212101 in words is "fourteen billion, five hundred forty million, two hundred twelve thousand, one hundred one".