14540325543313 has 2 divisors, whose sum is σ = 14540325543314. Its totient is φ = 14540325543312.

The previous prime is 14540325543311. The next prime is 14540325543371. The reversal of 14540325543313 is 31334552304541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13694492168449 + 845833374864 = 3700607^2 + 919692^2 .

It is a cyclic number.

It is not a de Polignac number, because 14540325543313 - 2¹ = 14540325543311 is a prime.

It is a super-2 number, since 2×14540325543313² (a number of 27 digits) contains 22 as substring.

Together with 14540325543311, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 14540325543313.

It is not a weakly prime, because it can be changed into another prime (14540325543311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270162771656 + 7270162771657.

It is an arithmetic number, because the mean of its divisors is an integer number (7270162771657).

Almost surely, 2^{14540325543313} is an apocalyptic number.

It is an amenable number.

14540325543313 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540325543313 is an equidigital number, since it uses as much as digits as its factorization.

14540325543313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296000, while the sum is 43.

Adding to 14540325543313 its reverse (31334552304541), we get a palindrome (45874877847854).

The spelling of 14540325543313 in words is "fourteen trillion, five hundred forty billion, three hundred twenty-five million, five hundred forty-three thousand, three hundred thirteen".