14540339993 has 2 divisors, whose sum is σ = 14540339994. Its totient is φ = 14540339992.

The previous prime is 14540339987. The next prime is 14540340013. The reversal of 14540339993 is 39993304541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11907829129 + 2632510864 = 109123^2 + 51308^2 .

It is an emirp because it is prime and its reverse (39993304541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14540339993 - 2⁶ = 14540339929 is a prime.

It is a super-2 number, since 2×14540339993² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14540339903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270169996 + 7270169997.

It is an arithmetic number, because the mean of its divisors is an integer number (7270169997).

Almost surely, 2^14540339993 is an apocalyptic number.

It is an amenable number.

14540339993 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540339993 is an equidigital number, since it uses as much as digits as its factorization.

14540339993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1574640, while the sum is 50.

The spelling of 14540339993 in words is "fourteen billion, five hundred forty million, three hundred thirty-nine thousand, nine hundred ninety-three".