14540340013 has 2 divisors, whose sum is σ = 14540340014. Its totient is φ = 14540340012.

The previous prime is 14540339993. The next prime is 14540340029. The reversal of 14540340013 is 31004304541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14516153289 + 24186724 = 120483^2 + 4918^2 .

It is a cyclic number.

It is not a de Polignac number, because 14540340013 - 2⁵ = 14540339981 is a prime.

It is a super-2 number, since 2×14540340013² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14540340013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14540340413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270170006 + 7270170007.

It is an arithmetic number, because the mean of its divisors is an integer number (7270170007).

Almost surely, 2^14540340013 is an apocalyptic number.

It is an amenable number.

14540340013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540340013 is an equidigital number, since it uses as much as digits as its factorization.

14540340013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 14540340013 its reverse (31004304541), we get a palindrome (45544644554).

The spelling of 14540340013 in words is "fourteen billion, five hundred forty million, three hundred forty thousand, thirteen".