14540341241 has 2 divisors, whose sum is σ = 14540341242. Its totient is φ = 14540341240.

The previous prime is 14540341219. The next prime is 14540341243. The reversal of 14540341241 is 14214304541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10978638841 + 3561702400 = 104779^2 + 59680^2 .

It is a cyclic number.

It is not a de Polignac number, because 14540341241 - 2³⁰ = 13466599417 is a prime.

It is a super-2 number, since 2×14540341241² (a number of 21 digits) contains 22 as substring.

Together with 14540341243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14540341243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270170620 + 7270170621.

It is an arithmetic number, because the mean of its divisors is an integer number (7270170621).

Almost surely, 2^14540341241 is an apocalyptic number.

It is an amenable number.

14540341241 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540341241 is an equidigital number, since it uses as much as digits as its factorization.

14540341241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 14540341241 its reverse (14214304541), we get a palindrome (28754645782).

The spelling of 14540341241 in words is "fourteen billion, five hundred forty million, three hundred forty-one thousand, two hundred forty-one".