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145404023551 = 193375221947
BaseRepresentation
bin1000011101101011000…
…0010101001011111111
3111220022110022201102121
42013122300111023333
54340241412223201
6150444144503411
713335150544003
oct2073260251377
9456273281377
10145404023551
1156735865006
122421b61ab67
1310933340677
147075220703
153bb03839a1
hex21dac152ff

145404023551 has 4 divisors (see below), whose sum is σ = 145479247432. Its totient is φ = 145328799672.

The previous prime is 145404023549. The next prime is 145404023561. The reversal of 145404023551 is 155320404541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145404023551 - 21 = 145404023549 is a prime.

It is a super-2 number, since 2×1454040235512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145404023561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37609041 + ... + 37612906.

It is an arithmetic number, because the mean of its divisors is an integer number (36369811858).

Almost surely, 2145404023551 is an apocalyptic number.

145404023551 is a deficient number, since it is larger than the sum of its proper divisors (75223881).

145404023551 is an equidigital number, since it uses as much as digits as its factorization.

145404023551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75223880.

The product of its (nonzero) digits is 48000, while the sum is 34.

The spelling of 145404023551 in words is "one hundred forty-five billion, four hundred four million, twenty-three thousand, five hundred fifty-one".

Divisors: 1 1933 75221947 145404023551