145405344330511 has 4 divisors (see below), whose sum is σ = 145708904548800. Its totient is φ = 145101784112224.

The previous prime is 145405344330457. The next prime is 145405344330599. The reversal of 145405344330511 is 115033443504541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145405344330511 - 2¹⁵ = 145405344297743 is a prime.

It is a super-3 number, since 3×145405344330511³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145405344340511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151780108426 + ... + 151780109383.

It is an arithmetic number, because the mean of its divisors is an integer number (36427226137200).

Almost surely, 2^{145405344330511} is an apocalyptic number.

145405344330511 is a deficient number, since it is larger than the sum of its proper divisors (303560218289).

145405344330511 is an equidigital number, since it uses as much as digits as its factorization.

145405344330511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 303560218288.

The product of its (nonzero) digits is 864000, while the sum is 43.

The spelling of 145405344330511 in words is "one hundred forty-five trillion, four hundred five billion, three hundred forty-four million, three hundred thirty thousand, five hundred eleven".