Base | Representation |
---|---|
bin | 1000011101101011010… |
… | …1101011000110010111 |
3 | 111220022112221212111221 |
4 | 2013122311223012113 |
5 | 4340242242032043 |
6 | 150444234511211 |
7 | 13335165466006 |
oct | 2073265530627 |
9 | 456275855457 |
10 | 145405424023 |
11 | 56736631222 |
12 | 2421bb95507 |
13 | 10933710c52 |
14 | 70754a6c3d |
15 | 3bb055d8ed |
hex | 21dad6b197 |
145405424023 has 2 divisors, whose sum is σ = 145405424024. Its totient is φ = 145405424022.
The previous prime is 145405423991. The next prime is 145405424053. The reversal of 145405424023 is 320424504541.
It is a strong prime.
It is an emirp because it is prime and its reverse (320424504541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 145405424023 - 25 = 145405423991 is a prime.
It is a super-2 number, since 2×1454054240232 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 145405424023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145405424053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72702712011 + 72702712012.
It is an arithmetic number, because the mean of its divisors is an integer number (72702712012).
Almost surely, 2145405424023 is an apocalyptic number.
145405424023 is a deficient number, since it is larger than the sum of its proper divisors (1).
145405424023 is an equidigital number, since it uses as much as digits as its factorization.
145405424023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 76800, while the sum is 34.
Adding to 145405424023 its reverse (320424504541), we get a palindrome (465829928564).
The spelling of 145405424023 in words is "one hundred forty-five billion, four hundred five million, four hundred twenty-four thousand, twenty-three".
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