145411135211 has 4 divisors (see below), whose sum is σ = 150101817024. Its totient is φ = 140720453400.

The previous prime is 145411135193. The next prime is 145411135231. The reversal of 145411135211 is 112531114541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-145411135211 is a prime.

It is a super-2 number, since 2×145411135211² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145411135231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2345340860 + ... + 2345340921.

It is an arithmetic number, because the mean of its divisors is an integer number (37525454256).

Almost surely, 2^145411135211 is an apocalyptic number.

145411135211 is a deficient number, since it is larger than the sum of its proper divisors (4690681813).

145411135211 is an equidigital number, since it uses as much as digits as its factorization.

145411135211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4690681812.

The product of its digits is 2400, while the sum is 29.

Adding to 145411135211 its reverse (112531114541), we get a palindrome (257942249752).

The spelling of 145411135211 in words is "one hundred forty-five billion, four hundred eleven million, one hundred thirty-five thousand, two hundred eleven".