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145413043122455 = 5941155919824289
BaseRepresentation
bin100001000100000010011100…
…110001111111000100010111
3201001212100110222212022100122
4201010002130301333010113
5123024421403014404310
61233133455123102155
742425513523461303
oct4104023461770427
9631770428768318
10145413043122455
1142373363a29049
1214386031b1195b
13631a511402824
1427ca0591c8d03
1511c27d8725555
hex84409cc7f117

145413043122455 has 16 divisors (see below), whose sum is σ = 174793143844800. Its totient is φ = 116132265047040.

The previous prime is 145413043122433. The next prime is 145413043122493. The reversal of 145413043122455 is 554221340314541.

It is not a de Polignac number, because 145413043122455 - 218 = 145413042860311 is a prime.

It is a super-2 number, since 2×1454130431224552 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2577050 + ... + 17247239.

It is an arithmetic number, because the mean of its divisors is an integer number (10924571490300).

Almost surely, 2145413043122455 is an apocalyptic number.

145413043122455 is a deficient number, since it is larger than the sum of its proper divisors (29380100722345).

145413043122455 is a wasteful number, since it uses less digits than its factorization.

145413043122455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19826794.

The product of its (nonzero) digits is 1152000, while the sum is 44.

Adding to 145413043122455 its reverse (554221340314541), we get a palindrome (699634383436996).

The spelling of 145413043122455 in words is "one hundred forty-five trillion, four hundred thirteen billion, forty-three million, one hundred twenty-two thousand, four hundred fifty-five".

Divisors: 1 5 941 1559 4705 7795 1467019 7335095 19824289 99121445 18654655949 30906066551 93273279745 154530332755 29082608624491 145413043122455