Base | Representation |
---|---|
bin | 100001000100000010011100… |
… | …110001111111000100010111 |
3 | 201001212100110222212022100122 |
4 | 201010002130301333010113 |
5 | 123024421403014404310 |
6 | 1233133455123102155 |
7 | 42425513523461303 |
oct | 4104023461770427 |
9 | 631770428768318 |
10 | 145413043122455 |
11 | 42373363a29049 |
12 | 14386031b1195b |
13 | 631a511402824 |
14 | 27ca0591c8d03 |
15 | 11c27d8725555 |
hex | 84409cc7f117 |
145413043122455 has 16 divisors (see below), whose sum is σ = 174793143844800. Its totient is φ = 116132265047040.
The previous prime is 145413043122433. The next prime is 145413043122493. The reversal of 145413043122455 is 554221340314541.
It is not a de Polignac number, because 145413043122455 - 218 = 145413042860311 is a prime.
It is a super-2 number, since 2×1454130431224552 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2577050 + ... + 17247239.
It is an arithmetic number, because the mean of its divisors is an integer number (10924571490300).
Almost surely, 2145413043122455 is an apocalyptic number.
145413043122455 is a deficient number, since it is larger than the sum of its proper divisors (29380100722345).
145413043122455 is a wasteful number, since it uses less digits than its factorization.
145413043122455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19826794.
The product of its (nonzero) digits is 1152000, while the sum is 44.
Adding to 145413043122455 its reverse (554221340314541), we get a palindrome (699634383436996).
The spelling of 145413043122455 in words is "one hundred forty-five trillion, four hundred thirteen billion, forty-three million, one hundred twenty-two thousand, four hundred fifty-five".
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