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145425255035 = 529085051007
BaseRepresentation
bin1000011101110000000…
…1010100101001111011
3111220100221021101112212
42013130001110221323
54340312331130120
6150450223525335
713335526162244
oct2073401245173
9456327241485
10145425255035
1156746846595
122422675984b
1310937865488
147077d89ccb
153bb21796c5
hex21dc054a7b

145425255035 has 4 divisors (see below), whose sum is σ = 174510306048. Its totient is φ = 116340204024.

The previous prime is 145425255023. The next prime is 145425255037. The reversal of 145425255035 is 530552524541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145425255035 - 218 = 145424992891 is a prime.

It is a super-2 number, since 2×1454252550352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145425254983 and 145425255001.

It is not an unprimeable number, because it can be changed into a prime (145425255037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14542525499 + ... + 14542525508.

It is an arithmetic number, because the mean of its divisors is an integer number (43627576512).

Almost surely, 2145425255035 is an apocalyptic number.

145425255035 is a deficient number, since it is larger than the sum of its proper divisors (29085051013).

145425255035 is an equidigital number, since it uses as much as digits as its factorization.

145425255035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29085051012.

The product of its (nonzero) digits is 600000, while the sum is 41.

Adding to 145425255035 its reverse (530552524541), we get a palindrome (675977779576).

The spelling of 145425255035 in words is "one hundred forty-five billion, four hundred twenty-five million, two hundred fifty-five thousand, thirty-five".

Divisors: 1 5 29085051007 145425255035