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145444111103321 is a prime number
BaseRepresentation
bin100001000100011111011000…
…100100111011010101011001
3201001222022200011202021001122
4201010133120210323111121
5123030424014420301241
61233200034025455025
742430663442115062
oct4104373044732531
9631868604667048
10145444111103321
1142385556aa7998
1214390062641475
136320422b17564
1427cb7653d9569
1511c3505ead04b
hex8447d893b559

145444111103321 has 2 divisors, whose sum is σ = 145444111103322. Its totient is φ = 145444111103320.

The previous prime is 145444111103281. The next prime is 145444111103387. The reversal of 145444111103321 is 123301111444541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 142941273198025 + 2502837905296 = 11955805^2 + 1582036^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145444111103321 is a prime.

It is not a weakly prime, because it can be changed into another prime (145444111103021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72722055551660 + 72722055551661.

It is an arithmetic number, because the mean of its divisors is an integer number (72722055551661).

Almost surely, 2145444111103321 is an apocalyptic number.

It is an amenable number.

145444111103321 is a deficient number, since it is larger than the sum of its proper divisors (1).

145444111103321 is an equidigital number, since it uses as much as digits as its factorization.

145444111103321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 35.

Adding to 145444111103321 its reverse (123301111444541), we get a palindrome (268745222547862).

The spelling of 145444111103321 in words is "one hundred forty-five trillion, four hundred forty-four billion, one hundred eleven million, one hundred three thousand, three hundred twenty-one".