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14545044249223 is a prime number
BaseRepresentation
bin1101001110101000100000…
…1100100001101010000111
31220111111022010211121120211
43103222020030201222013
53401301222311433343
650533522344540251
73030562520131615
oct323521014415207
956444263747524
1014545044249223
1146a8578321234
12176ab15a81687
13816790206817
14383dabb5c6b5
151a353b2b079d
hexd3a88321a87

14545044249223 has 2 divisors, whose sum is σ = 14545044249224. Its totient is φ = 14545044249222.

The previous prime is 14545044249173. The next prime is 14545044249271. The reversal of 14545044249223 is 32294244054541.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14545044249223 is a prime.

It is a super-2 number, since 2×145450442492232 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14545044249293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7272522124611 + 7272522124612.

It is an arithmetic number, because the mean of its divisors is an integer number (7272522124612).

Almost surely, 214545044249223 is an apocalyptic number.

14545044249223 is a deficient number, since it is larger than the sum of its proper divisors (1).

14545044249223 is an equidigital number, since it uses as much as digits as its factorization.

14545044249223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5529600, while the sum is 49.

The spelling of 14545044249223 in words is "fourteen trillion, five hundred forty-five billion, forty-four million, two hundred forty-nine thousand, two hundred twenty-three".