Base | Representation |
---|---|
bin | 1000011101111001111… |
… | …1000010101010010001 |
3 | 111220110211001221021212 |
4 | 2013132133002222101 |
5 | 4340403422200311 |
6 | 150454302025505 |
7 | 13336540461605 |
oct | 2073637025221 |
9 | 456424057255 |
10 | 145466600081 |
11 | 56768115750 |
12 | 24238578295 |
13 | 109432b02ba |
14 | 707d66d505 |
15 | 3bb5ae4c8b |
hex | 21de7c2a91 |
145466600081 has 4 divisors (see below), whose sum is σ = 158690836464. Its totient is φ = 132242363700.
The previous prime is 145466600057. The next prime is 145466600089. The reversal of 145466600081 is 180006664541.
145466600081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 180006664541 = 11 ⋅16364242231.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145466600081 is a prime.
It is a super-2 number, since 2×1454666000812 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145466600089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6612118175 + ... + 6612118196.
It is an arithmetic number, because the mean of its divisors is an integer number (39672709116).
Almost surely, 2145466600081 is an apocalyptic number.
145466600081 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
145466600081 is a deficient number, since it is larger than the sum of its proper divisors (13224236383).
145466600081 is a wasteful number, since it uses less digits than its factorization.
145466600081 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13224236382.
The product of its (nonzero) digits is 138240, while the sum is 41.
It can be divided in two parts, 145466 and 600081, that added together give a palindrome (745547).
The spelling of 145466600081 in words is "one hundred forty-five billion, four hundred sixty-six million, six hundred thousand, eighty-one".
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