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1454763090049 is a prime number
BaseRepresentation
bin10101001010110110101…
…000110010000010000001
312011001222221102000022021
4111022312220302002001
5142313323322340144
63032150421441441
7210050246144503
oct25126650620201
95131887360267
101454763090049
11510a639253a5
121b5b39270281
13a72503c6c79
14505a776bd73
1527c95c60884
hex152b6a32081

1454763090049 has 2 divisors, whose sum is σ = 1454763090050. Its totient is φ = 1454763090048.

The previous prime is 1454763090031. The next prime is 1454763090073. The reversal of 1454763090049 is 9400903674541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1441476378225 + 13286711824 = 1200615^2 + 115268^2 .

It is an emirp because it is prime and its reverse (9400903674541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1454763090049 - 217 = 1454762958977 is a prime.

It is a super-3 number, since 3×14547630900493 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1454763089978 and 1454763090005.

It is not a weakly prime, because it can be changed into another prime (1454763094049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727381545024 + 727381545025.

It is an arithmetic number, because the mean of its divisors is an integer number (727381545025).

Almost surely, 21454763090049 is an apocalyptic number.

It is an amenable number.

1454763090049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1454763090049 is an equidigital number, since it uses as much as digits as its factorization.

1454763090049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 52.

The spelling of 1454763090049 in words is "one trillion, four hundred fifty-four billion, seven hundred sixty-three million, ninety thousand, forty-nine".