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1454763090073 is a prime number
BaseRepresentation
bin10101001010110110101…
…000110010000010011001
312011001222221102000100011
4111022312220302002121
5142313323322340243
63032150421441521
7210050246144536
oct25126650620231
95131887360304
101454763090073
11510a63925417
121b5b392702a1
13a72503c6c97
14505a776bd8d
1527c95c6089d
hex152b6a32099

1454763090073 has 2 divisors, whose sum is σ = 1454763090074. Its totient is φ = 1454763090072.

The previous prime is 1454763090049. The next prime is 1454763090083. The reversal of 1454763090073 is 3700903674541.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 983931076489 + 470832013584 = 991933^2 + 686172^2 .

It is a cyclic number.

It is not a de Polignac number, because 1454763090073 - 29 = 1454763089561 is a prime.

It is a super-2 number, since 2×14547630900732 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1454763089999 and 1454763090026.

It is not a weakly prime, because it can be changed into another prime (1454763090083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727381545036 + 727381545037.

It is an arithmetic number, because the mean of its divisors is an integer number (727381545037).

Almost surely, 21454763090073 is an apocalyptic number.

It is an amenable number.

1454763090073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1454763090073 is an equidigital number, since it uses as much as digits as its factorization.

1454763090073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1905120, while the sum is 49.

The spelling of 1454763090073 in words is "one trillion, four hundred fifty-four billion, seven hundred sixty-three million, ninety thousand, seventy-three".