Base | Representation |
---|---|
bin | 100001000101100000111000… |
… | …000110111111011111011111 |
3 | 201002020001012001110022002212 |
4 | 201011200320012333133133 |
5 | 123033102024414024003 |
6 | 1233252224031311035 |
7 | 42436033211242235 |
oct | 4105407006773737 |
9 | 632201161408085 |
10 | 145514433345503 |
11 | 42402363085312 |
12 | 143a180937b47b |
13 | 6326c4bc49851 |
14 | 27d0d16b34955 |
15 | 11c526ea22dd8 |
hex | 8458381bf7df |
145514433345503 has 2 divisors, whose sum is σ = 145514433345504. Its totient is φ = 145514433345502.
The previous prime is 145514433345469. The next prime is 145514433345577. The reversal of 145514433345503 is 305543334415541.
It is a weak prime.
It is an emirp because it is prime and its reverse (305543334415541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 145514433345503 - 216 = 145514433279967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145514433345403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72757216672751 + 72757216672752.
It is an arithmetic number, because the mean of its divisors is an integer number (72757216672752).
Almost surely, 2145514433345503 is an apocalyptic number.
145514433345503 is a deficient number, since it is larger than the sum of its proper divisors (1).
145514433345503 is an equidigital number, since it uses as much as digits as its factorization.
145514433345503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960000, while the sum is 50.
The spelling of 145514433345503 in words is "one hundred forty-five trillion, five hundred fourteen billion, four hundred thirty-three million, three hundred forty-five thousand, five hundred three".
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