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145520034151 = 206383705097
BaseRepresentation
bin1000011110000110101…
…0111000000101100111
3111220121112121200001111
42013201222320011213
54341011112043101
6150503451205451
713341056611222
oct2074152700547
9456545550044
10145520034151
11567952a1538
1224252446887
131095139b7ab
1470867bc5b9
153bba64c251
hex21e1ab8167

145520034151 has 4 divisors (see below), whose sum is σ = 145520945632. Its totient is φ = 145519122672.

The previous prime is 145520034131. The next prime is 145520034157. The reversal of 145520034151 is 151430025541.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 145520034151 - 29 = 145520033639 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145520034157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146166 + ... + 558931.

It is an arithmetic number, because the mean of its divisors is an integer number (36380236408).

Almost surely, 2145520034151 is an apocalyptic number.

145520034151 is a deficient number, since it is larger than the sum of its proper divisors (911481).

145520034151 is an equidigital number, since it uses as much as digits as its factorization.

145520034151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 911480.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 145520034151 its reverse (151430025541), we get a palindrome (296950059692).

The spelling of 145520034151 in words is "one hundred forty-five billion, five hundred twenty million, thirty-four thousand, one hundred fifty-one".

Divisors: 1 206383 705097 145520034151