Base | Representation |
---|---|
bin | 100001000101101010110011… |
… | …111010001111010111110011 |
3 | 201002021001201110020100022222 |
4 | 201011222303322033113303 |
5 | 123033240401134441201 |
6 | 1233301150321351255 |
7 | 42436561435044125 |
oct | 4105526372172763 |
9 | 632231643210288 |
10 | 145525100312051 |
11 | 42406937327149 |
12 | 143a38a579852b |
13 | 6327c5bb7b785 |
14 | 27d16496b3215 |
15 | 11c569622a91b |
hex | 845ab3e8f5f3 |
145525100312051 has 4 divisors (see below), whose sum is σ = 151852278586512. Its totient is φ = 139197922037592.
The previous prime is 145525100312023. The next prime is 145525100312089. The reversal of 145525100312051 is 150213001525541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 145525100312051 - 210 = 145525100311027 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145525100312951) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3163589137196 + ... + 3163589137241.
It is an arithmetic number, because the mean of its divisors is an integer number (37963069646628).
Almost surely, 2145525100312051 is an apocalyptic number.
145525100312051 is a deficient number, since it is larger than the sum of its proper divisors (6327178274461).
145525100312051 is an equidigital number, since it uses as much as digits as its factorization.
145525100312051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6327178274460.
The product of its (nonzero) digits is 30000, while the sum is 35.
Adding to 145525100312051 its reverse (150213001525541), we get a palindrome (295738101837592).
The spelling of 145525100312051 in words is "one hundred forty-five trillion, five hundred twenty-five billion, one hundred million, three hundred twelve thousand, fifty-one".
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