Base | Representation |
---|---|
bin | 1101001111000111011101… |
… | …1111110010101000110111 |
3 | 1220112021202021010210001212 |
4 | 3103301313133302220313 |
5 | 3401420232112141211 |
6 | 50541415112112035 |
7 | 3031305452052011 |
oct | 323616737625067 |
9 | 56467667123055 |
10 | 14553354021431 |
11 | 4701051a38075 |
12 | 177065499561b |
13 | 8174b59896b4 |
14 | 3845596211b1 |
15 | 1a3875a9a38b |
hex | d3c777f2a37 |
14553354021431 has 2 divisors, whose sum is σ = 14553354021432. Its totient is φ = 14553354021430.
The previous prime is 14553354021397. The next prime is 14553354021443. The reversal of 14553354021431 is 13412045335541.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14553354021431 is a prime.
It is a super-2 number, since 2×145533540214312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14553354021931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7276677010715 + 7276677010716.
It is an arithmetic number, because the mean of its divisors is an integer number (7276677010716).
Almost surely, 214553354021431 is an apocalyptic number.
14553354021431 is a deficient number, since it is larger than the sum of its proper divisors (1).
14553354021431 is an equidigital number, since it uses as much as digits as its factorization.
14553354021431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 41.
Adding to 14553354021431 its reverse (13412045335541), we get a palindrome (27965399356972).
The spelling of 14553354021431 in words is "fourteen trillion, five hundred fifty-three billion, three hundred fifty-four million, twenty-one thousand, four hundred thirty-one".
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