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1455563315201 is a prime number
BaseRepresentation
bin10101001011100110010…
…101011001100000000001
312011011001201011122211212
4111023212111121200001
5142321443202041301
63032402045215505
7210106134016442
oct25134625314001
95134051148755
101455563315201
115113345aa3a6
121b6121261595
13a734a128488
1450641b552c9
1527ce112e4bb
hex152e6559801

1455563315201 has 2 divisors, whose sum is σ = 1455563315202. Its totient is φ = 1455563315200.

The previous prime is 1455563315099. The next prime is 1455563315209. The reversal of 1455563315201 is 1025133655541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1454071810801 + 1491504400 = 1205849^2 + 38620^2 .

It is an emirp because it is prime and its reverse (1025133655541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1455563315201 is a prime.

It is not a weakly prime, because it can be changed into another prime (1455563315209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727781657600 + 727781657601.

It is an arithmetic number, because the mean of its divisors is an integer number (727781657601).

Almost surely, 21455563315201 is an apocalyptic number.

It is an amenable number.

1455563315201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1455563315201 is an equidigital number, since it uses as much as digits as its factorization.

1455563315201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270000, while the sum is 41.

The spelling of 1455563315201 in words is "one trillion, four hundred fifty-five billion, five hundred sixty-three million, three hundred fifteen thousand, two hundred one".