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14575110629983 is a prime number
BaseRepresentation
bin1101010000011000100001…
…0010101010101001011111
31220121100220112001000020121
43110012020102222221133
53402244311310124413
650555414031455411
73033005554141441
oct324061022525137
956540815030217
1014575110629983
11470a2a6a840a2
121774907087567
13819572270c77
14385620d26491
151a41eab4cb8d
hexd41884aaa5f

14575110629983 has 2 divisors, whose sum is σ = 14575110629984. Its totient is φ = 14575110629982.

The previous prime is 14575110629927. The next prime is 14575110629987. The reversal of 14575110629983 is 38992601157541.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14575110629983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14575110629987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7287555314991 + 7287555314992.

It is an arithmetic number, because the mean of its divisors is an integer number (7287555314992).

It is a 1-persistent number, because it is pandigital, but 2⋅14575110629983 = 29150221259966 is not.

Almost surely, 214575110629983 is an apocalyptic number.

14575110629983 is a deficient number, since it is larger than the sum of its proper divisors (1).

14575110629983 is an equidigital number, since it uses as much as digits as its factorization.

14575110629983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16329600, while the sum is 61.

The spelling of 14575110629983 in words is "fourteen trillion, five hundred seventy-five billion, one hundred ten million, six hundred twenty-nine thousand, nine hundred eighty-three".