Base | Representation |
---|---|
bin | 11011001100011101… |
… | …00110011100101111 |
3 | 1101200111111010021121 |
4 | 31212032212130233 |
5 | 214400100133143 |
6 | 10412424441411 |
7 | 1024541666323 |
oct | 154616463457 |
9 | 41614433247 |
10 | 14600005423 |
11 | 6212360193 |
12 | 29b5619267 |
13 | 14b8a0a083 |
14 | 9c7061983 |
15 | 5a6b527ed |
hex | 3663a672f |
14600005423 has 2 divisors, whose sum is σ = 14600005424. Its totient is φ = 14600005422.
The previous prime is 14600005373. The next prime is 14600005439. The reversal of 14600005423 is 32450000641.
It is a strong prime.
It is an emirp because it is prime and its reverse (32450000641) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14600005423 - 217 = 14599874351 is a prime.
It is a super-3 number, since 3×146000054233 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14600005493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7300002711 + 7300002712.
It is an arithmetic number, because the mean of its divisors is an integer number (7300002712).
Almost surely, 214600005423 is an apocalyptic number.
14600005423 is a deficient number, since it is larger than the sum of its proper divisors (1).
14600005423 is an equidigital number, since it uses as much as digits as its factorization.
14600005423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
The spelling of 14600005423 in words is "fourteen billion, six hundred million, five thousand, four hundred twenty-three".
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