Base | Representation |
---|---|
bin | 11011001100011111… |
… | …11111011110000101 |
3 | 1101200112011122110102 |
4 | 31212033333132011 |
5 | 214400143320203 |
6 | 10412440333445 |
7 | 1024545045353 |
oct | 154617773605 |
9 | 41615148412 |
10 | 14600370053 |
11 | 621258a135 |
12 | 29b5774285 |
13 | 14b8b07029 |
14 | 9c71187d3 |
15 | 5a6bc5888 |
hex | 3663ff785 |
14600370053 has 2 divisors, whose sum is σ = 14600370054. Its totient is φ = 14600370052.
The previous prime is 14600370047. The next prime is 14600370079. The reversal of 14600370053 is 35007300641.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10326217924 + 4274152129 = 101618^2 + 65377^2 .
It is a cyclic number.
It is not a de Polignac number, because 14600370053 - 230 = 13526628229 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14600369998 and 14600370025.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14600370023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7300185026 + 7300185027.
It is an arithmetic number, because the mean of its divisors is an integer number (7300185027).
Almost surely, 214600370053 is an apocalyptic number.
It is an amenable number.
14600370053 is a deficient number, since it is larger than the sum of its proper divisors (1).
14600370053 is an equidigital number, since it uses as much as digits as its factorization.
14600370053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 29.
Adding to 14600370053 its reverse (35007300641), we get a palindrome (49607670694).
The spelling of 14600370053 in words is "fourteen billion, six hundred million, three hundred seventy thousand, fifty-three".
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