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146010350143 = 7193110801979
BaseRepresentation
bin1000011111111011100…
…1010010001000111111
3111221212201020022011001
42013332321102020333
54343012122201033
6151024244311131
713356162333010
oct2077671221077
9457781208131
10146010350143
1156a17044169
122436a6a24a7
13109cbb42ab8
1470d1973007
153be8700e7d
hex21fee5223f

146010350143 has 8 divisors (see below), whose sum is σ = 166955402880. Its totient is φ = 125086905240.

The previous prime is 146010350107. The next prime is 146010350243. The reversal of 146010350143 is 341053010641.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-146010350143 is a prime.

It is a super-3 number, since 3×1460103501433 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (146010350243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5387473 + ... + 5414506.

It is an arithmetic number, because the mean of its divisors is an integer number (20869425360).

Almost surely, 2146010350143 is an apocalyptic number.

146010350143 is a deficient number, since it is larger than the sum of its proper divisors (20945052737).

146010350143 is a wasteful number, since it uses less digits than its factorization.

146010350143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10803917.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 146010350143 its reverse (341053010641), we get a palindrome (487063360784).

The spelling of 146010350143 in words is "one hundred forty-six billion, ten million, three hundred fifty thousand, one hundred forty-three".

Divisors: 1 7 1931 13517 10801979 75613853 20858621449 146010350143