146017433 has 4 divisors (see below), whose sum is σ = 146175540. Its totient is φ = 145859328.

The previous prime is 146017427. The next prime is 146017439. The reversal of 146017433 is 334710641.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334710641 = 47 ⋅7121503.

It is an interprime number because it is at equal distance from previous prime (146017427) and next prime (146017439).

It can be written as a sum of positive squares in 2 ways, for example, as 76177984 + 69839449 = 8728^2 + 8357^2 .

It is a cyclic number.

It is not a de Polignac number, because 146017433 - 2²⁴ = 129240217 is a prime.

It is a super-4 number, since 4×146017433⁴ (a number of 34 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 146017396 and 146017405.

It is not an unprimeable number, because it can be changed into a prime (146017439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77660 + ... + 79517.

It is an arithmetic number, because the mean of its divisors is an integer number (36543885).

Almost surely, 2^146017433 is an apocalyptic number.

It is an amenable number.

146017433 is a deficient number, since it is larger than the sum of its proper divisors (158107).

146017433 is an equidigital number, since it uses as much as digits as its factorization.

146017433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 158106.

The product of its (nonzero) digits is 6048, while the sum is 29.

The square root of 146017433 is about 12083.7673347346. The cubic root of 146017433 is about 526.5846999413.

The spelling of 146017433 in words is "one hundred forty-six million, seventeen thousand, four hundred thirty-three".