Base | Representation |
---|---|
bin | 10101010000000101011… |
… | …000001101011011111101 |
3 | 12011121111022221112210012 |
4 | 111100011120031123331 |
5 | 142411324023110323 |
6 | 3034520000353005 |
7 | 210336361435046 |
oct | 25200530153375 |
9 | 5147438845705 |
10 | 1460379113213 |
11 | 513385a34759 |
12 | 1b7046015765 |
13 | a7936a716b7 |
14 | 5097b5878cd |
15 | 27ec3cec678 |
hex | 1540560d6fd |
1460379113213 has 2 divisors, whose sum is σ = 1460379113214. Its totient is φ = 1460379113212.
The previous prime is 1460379113183. The next prime is 1460379113227. The reversal of 1460379113213 is 3123119730641.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 911419630489 + 548959482724 = 954683^2 + 740918^2 .
It is a cyclic number.
It is not a de Polignac number, because 1460379113213 - 212 = 1460379109117 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1460379113813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 730189556606 + 730189556607.
It is an arithmetic number, because the mean of its divisors is an integer number (730189556607).
Almost surely, 21460379113213 is an apocalyptic number.
It is an amenable number.
1460379113213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1460379113213 is an equidigital number, since it uses as much as digits as its factorization.
1460379113213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 41.
The spelling of 1460379113213 in words is "one trillion, four hundred sixty billion, three hundred seventy-nine million, one hundred thirteen thousand, two hundred thirteen".
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