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146102106131 is a prime number
BaseRepresentation
bin1000100000010001011…
…1010011100000010011
3111222010002212222200222
42020010113103200103
54343204114344011
6151041323103255
713361355261122
oct2100427234023
9458102788628
10146102106131
1156a63914863
1224395371b2b
1310a14b5b097
1470ddc19ab9
153c017c7ddb
hex22045d3813

146102106131 has 2 divisors, whose sum is σ = 146102106132. Its totient is φ = 146102106130.

The previous prime is 146102106119. The next prime is 146102106133. The reversal of 146102106131 is 131601201641.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 146102106131 - 26 = 146102106067 is a prime.

It is a super-2 number, since 2×1461021061312 (a number of 23 digits) contains 22 as substring.

Together with 146102106133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 146102106131.

It is not a weakly prime, because it can be changed into another prime (146102106133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73051053065 + 73051053066.

It is an arithmetic number, because the mean of its divisors is an integer number (73051053066).

Almost surely, 2146102106131 is an apocalyptic number.

146102106131 is a deficient number, since it is larger than the sum of its proper divisors (1).

146102106131 is an equidigital number, since it uses as much as digits as its factorization.

146102106131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 26.

Adding to 146102106131 its reverse (131601201641), we get a palindrome (277703307772).

The spelling of 146102106131 in words is "one hundred forty-six billion, one hundred two million, one hundred six thousand, one hundred thirty-one".