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14612953601 is a prime number
BaseRepresentation
bin11011001101111111…
…11111101000000001
31101201101211221211202
431212333333220001
5214411404003401
610414010150545
71025060025161
oct154677775001
941641757752
1014612953601
1162196a4364
1229b9a22455
1314bb5c180c
149c8a725a1
155a7d5e06b
hex366fffa01

14612953601 has 2 divisors, whose sum is σ = 14612953602. Its totient is φ = 14612953600.

The previous prime is 14612953571. The next prime is 14612953603. The reversal of 14612953601 is 10635921641.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11417991025 + 3194962576 = 106855^2 + 56524^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14612953601 is a prime.

Together with 14612953603, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14612953603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7306476800 + 7306476801.

It is an arithmetic number, because the mean of its divisors is an integer number (7306476801).

Almost surely, 214612953601 is an apocalyptic number.

It is an amenable number.

14612953601 is a deficient number, since it is larger than the sum of its proper divisors (1).

14612953601 is an equidigital number, since it uses as much as digits as its factorization.

14612953601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 38.

The spelling of 14612953601 in words is "fourteen billion, six hundred twelve million, nine hundred fifty-three thousand, six hundred one".