14621111420131 has 4 divisors (see below), whose sum is σ = 14658697825200. Its totient is φ = 14583525015064.

The previous prime is 14621111420117. The next prime is 14621111420137. The reversal of 14621111420131 is 13102411112641.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14621111420131 - 2⁹ = 14621111419619 is a prime.

It is a super-2 number, since 2×14621111420131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14621111420131.

It is not an unprimeable number, because it can be changed into a prime (14621111420137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18793201951 + ... + 18793202728.

It is an arithmetic number, because the mean of its divisors is an integer number (3664674456300).

Almost surely, 2^{14621111420131} is an apocalyptic number.

14621111420131 is a deficient number, since it is larger than the sum of its proper divisors (37586405069).

14621111420131 is an equidigital number, since it uses as much as digits as its factorization.

14621111420131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37586405068.

The product of its (nonzero) digits is 1152, while the sum is 28.

Adding to 14621111420131 its reverse (13102411112641), we get a palindrome (27723522532772).

The spelling of 14621111420131 in words is "fourteen trillion, six hundred twenty-one billion, one hundred eleven million, four hundred twenty thousand, one hundred thirty-one".