Base | Representation |
---|---|
bin | 11011010000100000… |
… | …11111100101110110 |
3 | 1101202212120001222002 |
4 | 31220100133211312 |
5 | 214432304243204 |
6 | 10420042335302 |
7 | 1025434265312 |
oct | 155020374566 |
9 | 41685501862 |
10 | 14634056054 |
11 | 622a5a7a02 |
12 | 2a04aba532 |
13 | 14c2a9c987 |
14 | 9cb7a6b42 |
15 | 5a9b2b91e |
hex | 36841f976 |
14634056054 has 4 divisors (see below), whose sum is σ = 21951084084. Its totient is φ = 7317028026.
The previous prime is 14634056039. The next prime is 14634056057. The reversal of 14634056054 is 45065043641.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×146340560542 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14634055999 and 14634056017.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14634056057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3658514012 + ... + 3658514015.
It is an arithmetic number, because the mean of its divisors is an integer number (5487771021).
Almost surely, 214634056054 is an apocalyptic number.
14634056054 is a deficient number, since it is larger than the sum of its proper divisors (7317028030).
14634056054 is an equidigital number, since it uses as much as digits as its factorization.
14634056054 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7317028029.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 14634056054 its reverse (45065043641), we get a palindrome (59699099695).
The spelling of 14634056054 in words is "fourteen billion, six hundred thirty-four million, fifty-six thousand, fifty-four".
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