Search a number
-
+
1464325136753 is a prime number
BaseRepresentation
bin10101010011110000100…
…101000110000101110001
312011222200100002022110012
4111103300211012011301
5142442414213334003
63040411321344305
7210536225202623
oct25236045060561
95158610068405
101464325136753
11515020401636
121b7967638095
13a8115444a7b
1450c3368ac13
152815545e8d8
hex154f0946171

1464325136753 has 2 divisors, whose sum is σ = 1464325136754. Its totient is φ = 1464325136752.

The previous prime is 1464325136683. The next prime is 1464325136759. The reversal of 1464325136753 is 3576315234641.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 903455953009 + 560869183744 = 950503^2 + 748912^2 .

It is a cyclic number.

It is not a de Polignac number, because 1464325136753 - 218 = 1464324874609 is a prime.

It is a super-2 number, since 2×14643251367532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1464325136759) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 732162568376 + 732162568377.

It is an arithmetic number, because the mean of its divisors is an integer number (732162568377).

Almost surely, 21464325136753 is an apocalyptic number.

It is an amenable number.

1464325136753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1464325136753 is an equidigital number, since it uses as much as digits as its factorization.

1464325136753 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5443200, while the sum is 50.

The spelling of 1464325136753 in words is "one trillion, four hundred sixty-four billion, three hundred twenty-five million, one hundred thirty-six thousand, seven hundred fifty-three".