Base | Representation |
---|---|
bin | 100001010011000010110011… |
… | …001101000000011010010011 |
3 | 201012111221002220000010001001 |
4 | 201103002303031000122103 |
5 | 123143320221113040020 |
6 | 1235243313023122431 |
7 | 42563150035624342 |
oct | 4123026315003223 |
9 | 635457086003031 |
10 | 146444211455635 |
11 | 42730706634a85 |
12 | 14511a52143417 |
13 | 6393825b1b062 |
14 | 2823d1acc5b59 |
15 | 11de53b44850a |
hex | 8530b3340693 |
146444211455635 has 4 divisors (see below), whose sum is σ = 175733053746768. Its totient is φ = 117155369164504.
The previous prime is 146444211455627. The next prime is 146444211455741. The reversal of 146444211455635 is 536554112444641.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 146444211455635 - 23 = 146444211455627 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14644421145559 + ... + 14644421145568.
It is an arithmetic number, because the mean of its divisors is an integer number (43933263436692).
Almost surely, 2146444211455635 is an apocalyptic number.
146444211455635 is a deficient number, since it is larger than the sum of its proper divisors (29288842291133).
146444211455635 is an equidigital number, since it uses as much as digits as its factorization.
146444211455635 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29288842291132.
The product of its digits is 27648000, while the sum is 55.
The spelling of 146444211455635 in words is "one hundred forty-six trillion, four hundred forty-four billion, two hundred eleven million, four hundred fifty-five thousand, six hundred thirty-five".
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