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146520350324741 is a prime number
BaseRepresentation
bin100001010100001001101101…
…011011101111100000000101
3201012210012122010201102012002
4201110021231123233200011
5123201042134140342431
61235342304131235045
742601513604422511
oct4124115533574005
9635705563642162
10146520350324741
114275aa27a87298
1214524760a48a85
13639aa6b033b23
1428278a0d39141
1511e14e59733cb
hex85426d6ef805

146520350324741 has 2 divisors, whose sum is σ = 146520350324742. Its totient is φ = 146520350324740.

The previous prime is 146520350324653. The next prime is 146520350324749. The reversal of 146520350324741 is 147423053025641.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 144082211730625 + 2438138594116 = 12003425^2 + 1561454^2 .

It is a cyclic number.

It is not a de Polignac number, because 146520350324741 - 234 = 146503170455557 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (146520350324749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73260175162370 + 73260175162371.

It is an arithmetic number, because the mean of its divisors is an integer number (73260175162371).

Almost surely, 2146520350324741 is an apocalyptic number.

It is an amenable number.

146520350324741 is a deficient number, since it is larger than the sum of its proper divisors (1).

146520350324741 is an equidigital number, since it uses as much as digits as its factorization.

146520350324741 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2419200, while the sum is 47.

The spelling of 146520350324741 in words is "one hundred forty-six trillion, five hundred twenty billion, three hundred fifty million, three hundred twenty-four thousand, seven hundred forty-one".