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14660127281 is a prime number
BaseRepresentation
bin11011010011100111…
…11100101000110001
31101211200121121222002
431221303330220301
5220010443033111
610422413223345
71026202011602
oct155163745061
941750547862
1014660127281
116243294678
122a11791b55
1314c82ca637
149d1031da9
155ac07b63b
hex369cfca31

14660127281 has 2 divisors, whose sum is σ = 14660127282. Its totient is φ = 14660127280.

The previous prime is 14660127277. The next prime is 14660127283. The reversal of 14660127281 is 18272106641.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13450200625 + 1209926656 = 115975^2 + 34784^2 .

It is a cyclic number.

It is not a de Polignac number, because 14660127281 - 22 = 14660127277 is a prime.

It is a super-2 number, since 2×146601272812 (a number of 21 digits) contains 22 as substring.

Together with 14660127283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14660127283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7330063640 + 7330063641.

It is an arithmetic number, because the mean of its divisors is an integer number (7330063641).

Almost surely, 214660127281 is an apocalyptic number.

It is an amenable number.

14660127281 is a deficient number, since it is larger than the sum of its proper divisors (1).

14660127281 is an equidigital number, since it uses as much as digits as its factorization.

14660127281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 38.

The spelling of 14660127281 in words is "fourteen billion, six hundred sixty million, one hundred twenty-seven thousand, two hundred eighty-one".