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146734044397 is a prime number
BaseRepresentation
bin1000100010101000000…
…1111101010011101101
3112000202010222210000221
42020222001331103231
54401002403410042
6151224135451341
713413130540543
oct2105201752355
9460663883027
10146734044397
11572585a7396
1224530b26b51
1310ab5a59c55
14715db17d93
153c3c003d67
hex222a07d4ed

146734044397 has 2 divisors, whose sum is σ = 146734044398. Its totient is φ = 146734044396.

The previous prime is 146734044383. The next prime is 146734044427. The reversal of 146734044397 is 793440437641.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90709994761 + 56024049636 = 301181^2 + 236694^2 .

It is an emirp because it is prime and its reverse (793440437641) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 146734044397 - 235 = 112374306029 is a prime.

It is a super-3 number, since 3×1467340443973 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (146734044497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73367022198 + 73367022199.

It is an arithmetic number, because the mean of its divisors is an integer number (73367022199).

Almost surely, 2146734044397 is an apocalyptic number.

It is an amenable number.

146734044397 is a deficient number, since it is larger than the sum of its proper divisors (1).

146734044397 is an equidigital number, since it uses as much as digits as its factorization.

146734044397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6096384, while the sum is 52.

The spelling of 146734044397 in words is "one hundred forty-six billion, seven hundred thirty-four million, forty-four thousand, three hundred ninety-seven".