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14676131 is a prime number
BaseRepresentation
bin110111111111…
…000010100011
31000121121212102
4313333002203
512224114011
61242321015
7235513361
oct67770243
930547772
1014676131
118314438
124ab916b
13306b102
141d40631
15144d73b
hexdff0a3

14676131 has 2 divisors, whose sum is σ = 14676132. Its totient is φ = 14676130.

The previous prime is 14676121. The next prime is 14676133. The reversal of 14676131 is 13167641.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14676131 - 210 = 14675107 is a prime.

It is a super-2 number, since 2×146761312 = 430777642258322, which contains 22 as substring.

Together with 14676133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14676094 and 14676103.

It is not a weakly prime, because it can be changed into another prime (14676133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7338065 + 7338066.

It is an arithmetic number, because the mean of its divisors is an integer number (7338066).

Almost surely, 214676131 is an apocalyptic number.

14676131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14676131 is an equidigital number, since it uses as much as digits as its factorization.

14676131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3024, while the sum is 29.

The square root of 14676131 is about 3830.9438784717. The cubic root of 14676131 is about 244.8333227009.

The spelling of 14676131 in words is "fourteen million, six hundred seventy-six thousand, one hundred thirty-one".