Base | Representation |
---|---|
bin | 11011010101110100… |
… | …11000001111100001 |
3 | 1101212222100122122112 |
4 | 31222322120033201 |
5 | 220030204343213 |
6 | 10424313045105 |
7 | 1026514650203 |
oct | 155272301741 |
9 | 41788318575 |
10 | 14678590433 |
11 | 6252755281 |
12 | 2a179b6795 |
13 | 14cc093390 |
14 | 9d367a773 |
15 | 5ad9c6ea8 |
hex | 36ae983e1 |
14678590433 has 4 divisors (see below), whose sum is σ = 15807712788. Its totient is φ = 13549468080.
The previous prime is 14678590411. The next prime is 14678590463. The reversal of 14678590433 is 33409587641.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1659095824 + 13019494609 = 40732^2 + 114103^2 .
It is a cyclic number.
It is not a de Polignac number, because 14678590433 - 212 = 14678586337 is a prime.
It is a super-2 number, since 2×146785904332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14678590463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 564561158 + ... + 564561183.
It is an arithmetic number, because the mean of its divisors is an integer number (3951928197).
Almost surely, 214678590433 is an apocalyptic number.
14678590433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
14678590433 is a deficient number, since it is larger than the sum of its proper divisors (1129122355).
14678590433 is a wasteful number, since it uses less digits than its factorization.
14678590433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1129122354.
The product of its (nonzero) digits is 2177280, while the sum is 50.
The spelling of 14678590433 in words is "fourteen billion, six hundred seventy-eight million, five hundred ninety thousand, four hundred thirty-three".
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