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1468024469213 is a prime number
BaseRepresentation
bin10101010111001101000…
…100111011011011011101
312012100020011000212120112
4111113031010323123131
5143023003231003323
63042222351055405
7211030005046511
oct25271504733335
95170204025515
101468024469213
115166495a5895
121b861a511565
13a85849938a3
14510a4ad6141
15282c00e3178
hex155cd13b6dd

1468024469213 has 2 divisors, whose sum is σ = 1468024469214. Its totient is φ = 1468024469212.

The previous prime is 1468024469101. The next prime is 1468024469281. The reversal of 1468024469213 is 3129644208641.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1464821248804 + 3203220409 = 1210298^2 + 56597^2 .

It is a cyclic number.

It is not a de Polignac number, because 1468024469213 - 28 = 1468024468957 is a prime.

It is a super-2 number, since 2×14680244692132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1468024469293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 734012234606 + 734012234607.

It is an arithmetic number, because the mean of its divisors is an integer number (734012234607).

Almost surely, 21468024469213 is an apocalyptic number.

It is an amenable number.

1468024469213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1468024469213 is an equidigital number, since it uses as much as digits as its factorization.

1468024469213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1990656, while the sum is 50.

The spelling of 1468024469213 in words is "one trillion, four hundred sixty-eight billion, twenty-four million, four hundred sixty-nine thousand, two hundred thirteen".