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146969501353 is a prime number
BaseRepresentation
bin1000100011100000010…
…0001001111010101001
3112001100120001020020221
42020320010021322221
54401443143020403
6151303350250041
713422020102143
oct2107004117251
9461316036227
10146969501353
11573694a7714
1224597956921
1310b22779cac
1471830c9c93
153c52a13dbd
hex2238109ea9

146969501353 has 2 divisors, whose sum is σ = 146969501354. Its totient is φ = 146969501352.

The previous prime is 146969501267. The next prime is 146969501363. The reversal of 146969501353 is 353105969641.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 146358274624 + 611226729 = 382568^2 + 24723^2 .

It is an emirp because it is prime and its reverse (353105969641) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 146969501353 - 29 = 146969500841 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 146969501353.

It is not a weakly prime, because it can be changed into another prime (146969501363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73484750676 + 73484750677.

It is an arithmetic number, because the mean of its divisors is an integer number (73484750677).

Almost surely, 2146969501353 is an apocalyptic number.

It is an amenable number.

146969501353 is a deficient number, since it is larger than the sum of its proper divisors (1).

146969501353 is an equidigital number, since it uses as much as digits as its factorization.

146969501353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2624400, while the sum is 52.

The spelling of 146969501353 in words is "one hundred forty-six billion, nine hundred sixty-nine million, five hundred one thousand, three hundred fifty-three".