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147280853609 is a prime number
BaseRepresentation
bin1000100100101010011…
…1110111101001101001
3112002011020220120020222
42021022213313221221
54403112344303414
6151354311455425
713432520412521
oct2111247675151
9462136816228
10147280853609
115750922522a
1224664087575
1310b72120cb6
1471b25b6681
153c7001668e
hex224a9f7a69

147280853609 has 2 divisors, whose sum is σ = 147280853610. Its totient is φ = 147280853608.

The previous prime is 147280853563. The next prime is 147280853611. The reversal of 147280853609 is 906358082741.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 147204203584 + 76650025 = 383672^2 + 8755^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-147280853609 is a prime.

Together with 147280853611, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (147280853689) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73640426804 + 73640426805.

It is an arithmetic number, because the mean of its divisors is an integer number (73640426805).

It is a 1-persistent number, because it is pandigital, but 2⋅147280853609 = 294561707218 is not.

Almost surely, 2147280853609 is an apocalyptic number.

It is an amenable number.

147280853609 is a deficient number, since it is larger than the sum of its proper divisors (1).

147280853609 is an equidigital number, since it uses as much as digits as its factorization.

147280853609 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 147280853609 in words is "one hundred forty-seven billion, two hundred eighty million, eight hundred fifty-three thousand, six hundred nine".