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147410144311223 is a prime number
BaseRepresentation
bin100001100001000110011001…
…010010011011011110110111
3201022221021100102002021212202
4201201012121102123132313
5123310131433420424343
61241303141352335115
743023013536466553
oct4141063122333667
9638837312067782
10147410144311223
1142a73322542072
12146490a70a449b
136433942221281
142858990a92863
151209721e9adb8
hex86119949b7b7

147410144311223 has 2 divisors, whose sum is σ = 147410144311224. Its totient is φ = 147410144311222.

The previous prime is 147410144311193. The next prime is 147410144311247. The reversal of 147410144311223 is 322113441014741.

147410144311223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (322113441014741) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 147410144311223 - 26 = 147410144311159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (147410144311253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73705072155611 + 73705072155612.

It is an arithmetic number, because the mean of its divisors is an integer number (73705072155612).

Almost surely, 2147410144311223 is an apocalyptic number.

147410144311223 is a deficient number, since it is larger than the sum of its proper divisors (1).

147410144311223 is an equidigital number, since it uses as much as digits as its factorization.

147410144311223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 38.

Adding to 147410144311223 its reverse (322113441014741), we get a palindrome (469523585325964).

The spelling of 147410144311223 in words is "one hundred forty-seven trillion, four hundred ten billion, one hundred forty-four million, three hundred eleven thousand, two hundred twenty-three".