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14742414571 is a prime number
BaseRepresentation
bin11011011101011011…
…10110010011101011
31102001102110020220111
431232231312103223
5220143024231241
610434513035151
71031221312333
oct155655662353
942042406814
1014742414571
1162857882a5
122a35255ab7
13150c37bb41
149dbd320c3
155b43d2c81
hex36eb764eb

14742414571 has 2 divisors, whose sum is σ = 14742414572. Its totient is φ = 14742414570.

The previous prime is 14742414517. The next prime is 14742414611. The reversal of 14742414571 is 17541424741.

Together with previous prime (14742414517) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (14742414611) can be obtained adding 14742414571 to its sum of digits (40).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14742414571 - 215 = 14742381803 is a prime.

It is a super-2 number, since 2×147424145712 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14742418571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7371207285 + 7371207286.

It is an arithmetic number, because the mean of its divisors is an integer number (7371207286).

Almost surely, 214742414571 is an apocalyptic number.

14742414571 is a deficient number, since it is larger than the sum of its proper divisors (1).

14742414571 is an equidigital number, since it uses as much as digits as its factorization.

14742414571 is an evil number, because the sum of its binary digits is even.

The product of its digits is 125440, while the sum is 40.

The spelling of 14742414571 in words is "fourteen billion, seven hundred forty-two million, four hundred fourteen thousand, five hundred seventy-one".