Base | Representation |
---|---|
bin | 11011011101011011… |
… | …10110010011101011 |
3 | 1102001102110020220111 |
4 | 31232231312103223 |
5 | 220143024231241 |
6 | 10434513035151 |
7 | 1031221312333 |
oct | 155655662353 |
9 | 42042406814 |
10 | 14742414571 |
11 | 62857882a5 |
12 | 2a35255ab7 |
13 | 150c37bb41 |
14 | 9dbd320c3 |
15 | 5b43d2c81 |
hex | 36eb764eb |
14742414571 has 2 divisors, whose sum is σ = 14742414572. Its totient is φ = 14742414570.
The previous prime is 14742414517. The next prime is 14742414611. The reversal of 14742414571 is 17541424741.
Together with previous prime (14742414517) it forms an Ormiston pair, because they use the same digits, order apart.
It is an a-pointer prime, because the next prime (14742414611) can be obtained adding 14742414571 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14742414571 - 215 = 14742381803 is a prime.
It is a super-2 number, since 2×147424145712 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14742418571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7371207285 + 7371207286.
It is an arithmetic number, because the mean of its divisors is an integer number (7371207286).
Almost surely, 214742414571 is an apocalyptic number.
14742414571 is a deficient number, since it is larger than the sum of its proper divisors (1).
14742414571 is an equidigital number, since it uses as much as digits as its factorization.
14742414571 is an evil number, because the sum of its binary digits is even.
The product of its digits is 125440, while the sum is 40.
The spelling of 14742414571 in words is "fourteen billion, seven hundred forty-two million, four hundred fourteen thousand, five hundred seventy-one".
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