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1474330334041 is a prime number
BaseRepresentation
bin10101011101000100111…
…011111001001101011001
312012221111121121222220201
4111131010323321031121
5143123412031142131
63045144211422201
7211342165032205
oct25350473711531
95187447558821
101474330334041
11519295046424
121b989a2b4961
13a904b231a56
14515023a3b05
152853d9e7761
hex15744ef9359

1474330334041 has 2 divisors, whose sum is σ = 1474330334042. Its totient is φ = 1474330334040.

The previous prime is 1474330333997. The next prime is 1474330334219. The reversal of 1474330334041 is 1404330334741.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1071181530441 + 403148803600 = 1034979^2 + 634940^2 .

It is a cyclic number.

It is not a de Polignac number, because 1474330334041 - 221 = 1474328236889 is a prime.

It is not a weakly prime, because it can be changed into another prime (1474330334641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 737165167020 + 737165167021.

It is an arithmetic number, because the mean of its divisors is an integer number (737165167021).

Almost surely, 21474330334041 is an apocalyptic number.

It is an amenable number.

1474330334041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1474330334041 is an equidigital number, since it uses as much as digits as its factorization.

1474330334041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 37.

Adding to 1474330334041 its reverse (1404330334741), we get a palindrome (2878660668782).

The spelling of 1474330334041 in words is "one trillion, four hundred seventy-four billion, three hundred thirty million, three hundred thirty-four thousand, forty-one".